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Puzzle of the day:
#1


This is a simple yet a little bit confusing puzzle. (asked in Infosys)

In a certain office, 1/3 of the workers are women, 1/2 of the women are married & 1/3 of the married women have children. If 3/4 of the men are married & 2/3 of the married men have children, what part of workers are without children?
1) 5/18
2) 11/18
3) 4/9
4) 17/18

"Literary education is of no value, if it is not able to build up a sound character"



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Reply
#2

Answer: Let total no. of workers be x
Number of women = x/3 and number of men = 2x/3
Women married=1/2 * x/3 = x/6
Women having children = 1/3 *x/6 =x/18
Married Men =3/4 *2x/3 = x/2
Men having Children =2/3 * x/2 = x/3
Workers with children = x/3 + x/18 = 7x/18
Hence, workers without children = x- 7x/18 = 11x/18

"Literary education is of no value, if it is not able to build up a sound character"


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